Base | Representation |
---|---|
bin | 1011001111000100000011… |
… | …0100101101000100010000 |
3 | 1121201222022121221010111210 |
4 | 2303301000310231010100 |
5 | 3104344242324014300 |
6 | 42135025123540120 |
7 | 2413335050136222 |
oct | 263610064550420 |
9 | 47658277833453 |
10 | 12353413501200 |
11 | 3a33064961122 |
12 | 147621122a640 |
13 | 6b7bca5303b5 |
14 | 309ca0934412 |
15 | 166519997050 |
hex | b3c40d2d110 |
12353413501200 has 120 divisors (see below), whose sum is σ = 40073014230400. Its totient is φ = 3252544289280.
The previous prime is 12353413501193. The next prime is 12353413501207. The reversal of 12353413501200 is 210531435321.
It is an interprime number because it is at equal distance from previous prime (12353413501193) and next prime (12353413501207).
It is a tau number, because it is divible by the number of its divisors (120).
It is a Harshad number since it is a multiple of its sum of digits (30).
It is not an unprimeable number, because it can be changed into a prime (12353413501207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 65060335 + ... + 65249934.
Almost surely, 212353413501200 is an apocalyptic number.
12353413501200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12353413501200 is an abundant number, since it is smaller than the sum of its proper divisors (27719600729200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12353413501200 is a wasteful number, since it uses less digits than its factorization.
12353413501200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 130310369 (or 130310358 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 12353413501200 its reverse (210531435321), we get a palindrome (12563944936521).
The spelling of 12353413501200 in words is "twelve trillion, three hundred fifty-three billion, four hundred thirteen million, five hundred one thousand, two hundred".
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