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12411314300 = 225271110115959
BaseRepresentation
bin10111000111100010…
…11010000001111100
31012000222002002111102
423203301122001330
5200404244024200
65411321312232
7616364300540
oct134361320174
935028062442
1012411314300
115299955150
1224a4635678
13122a437c78
1485a4c9a20
154c991b6d5
hex2e3c5a07c

12411314300 has 144 divisors (see below), whose sum is σ = 33912829440. Its totient is φ = 3829920000.

The previous prime is 12411314297. The next prime is 12411314317. The reversal of 12411314300 is 341311421.

12411314300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 769721 + ... + 785679.

It is an arithmetic number, because the mean of its divisors is an integer number (235505760).

Almost surely, 212411314300 is an apocalyptic number.

12411314300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12411314300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16956414720).

12411314300 is an abundant number, since it is smaller than the sum of its proper divisors (21501515140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12411314300 is a wasteful number, since it uses less digits than its factorization.

12411314300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16092 (or 16085 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 12411314300 its reverse (341311421), we get a palindrome (12752625721).

The spelling of 12411314300 in words is "twelve billion, four hundred eleven million, three hundred fourteen thousand, three hundred".

Divisors: 1 2 4 5 7 10 11 14 20 22 25 28 35 44 50 55 70 77 100 101 110 140 154 175 202 220 275 308 350 385 404 505 550 700 707 770 1010 1100 1111 1414 1540 1925 2020 2222 2525 2828 3535 3850 4444 5050 5555 7070 7700 7777 10100 11110 14140 15554 15959 17675 22220 27775 31108 31918 35350 38885 55550 63836 70700 77770 79795 111100 111713 155540 159590 175549 194425 223426 319180 351098 388850 398975 446852 558565 702196 777700 797950 877745 1117130 1228843 1595900 1611859 1755490 2234260 2457686 2792825 3223718 3510980 4388725 4915372 5585650 6144215 6447436 8059295 8777450 11171300 11283013 12288430 16118590 17554900 17730449 22566026 24576860 30721075 32237180 35460898 40296475 45132052 56415065 61442150 70921796 80592950 88652245 112830130 122884300 124113143 161185900 177304490 225660260 248226286 282075325 354608980 443261225 496452572 564150650 620565715 886522450 1128301300 1241131430 1773044900 2482262860 3102828575 6205657150 12411314300