Base | Representation |
---|---|
bin | 1011111010111000000111… |
… | …0100110000101111100100 |
3 | 1201101221012021020100121020 |
4 | 2332232001310300233210 |
5 | 3204212320031441400 |
6 | 43512511523251140 |
7 | 2521612645022640 |
oct | 276560164605744 |
9 | 51357167210536 |
10 | 13106123312100 |
11 | 41a3303a2a905 |
12 | 157807a219ab0 |
13 | 740b95c7a250 |
14 | 3344a83d3c20 |
15 | 17adc12662a0 |
hex | beb81d30be4 |
13106123312100 has 144 divisors (see below), whose sum is σ = 46671241266048. Its totient is φ = 2765247989760.
The previous prime is 13106123312063. The next prime is 13106123312173. The reversal of 13106123312100 is 121332160131.
It is a super-3 number, since 3×131061233121003 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 240011589 + ... + 240066188.
Almost surely, 213106123312100 is an apocalyptic number.
13106123312100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13106123312100 is an abundant number, since it is smaller than the sum of its proper divisors (33565117953948).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13106123312100 is a wasteful number, since it uses less digits than its factorization.
13106123312100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 480077814 (or 480077807 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 13106123312100 its reverse (121332160131), we get a palindrome (13227455472231).
The spelling of 13106123312100 in words is "thirteen trillion, one hundred six billion, one hundred twenty-three million, three hundred twelve thousand, one hundred".
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