Base | Representation |
---|---|
bin | 10011000110000101110… |
… | …101000111101111001010 |
3 | 11122110001012012222211110 |
4 | 103012011311013233022 |
5 | 132444401320222310 |
6 | 2442453205111150 |
7 | 163542536455050 |
oct | 23060565075712 |
9 | 4573035188743 |
10 | 1312210320330 |
11 | 466561575618 |
12 | 1923946b84b6 |
13 | 969829ba860 |
14 | 477230b41d0 |
15 | 24200d8cd20 |
hex | 13185d47bca |
1312210320330 has 128 divisors (see below), whose sum is σ = 4080071116800. Its totient is φ = 262290265344.
The previous prime is 1312210320319. The next prime is 1312210320347. The reversal of 1312210320330 is 330230122131.
It is a super-2 number, since 2×13122103203302 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 1312210320297 and 1312210320306.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 12597160 + ... + 12700899.
It is an arithmetic number, because the mean of its divisors is an integer number (31875555600).
Almost surely, 21312210320330 is an apocalyptic number.
1312210320330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1312210320330 is an abundant number, since it is smaller than the sum of its proper divisors (2767860796470).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312210320330 is a wasteful number, since it uses less digits than its factorization.
1312210320330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25298108.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1312210320330 its reverse (330230122131), we get a palindrome (1642440442461).
The spelling of 1312210320330 in words is "one trillion, three hundred twelve billion, two hundred ten million, three hundred twenty thousand, three hundred thirty".
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