Base | Representation |
---|---|
bin | 1011111100000000000011… |
… | …1001110100100100010100 |
3 | 1201110210001010222121211212 |
4 | 2333000000321310210110 |
5 | 3210021342403322400 |
6 | 43525424112320552 |
7 | 2523165343336136 |
oct | 277000071644424 |
9 | 51423033877755 |
10 | 13125435214100 |
11 | 4200513aa96a0 |
12 | 157b969843158 |
13 | 742952c21cb1 |
14 | 3353bb15d056 |
15 | 17b6518b1335 |
hex | bf000e74914 |
13125435214100 has 72 divisors (see below), whose sum is σ = 31379123545056. Its totient is φ = 4725629200000.
The previous prime is 13125435214043. The next prime is 13125435214153. The reversal of 13125435214100 is 141253452131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 58959266 + ... + 59181465.
It is an arithmetic number, because the mean of its divisors is an integer number (435821160348).
Almost surely, 213125435214100 is an apocalyptic number.
13125435214100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13125435214100 is an abundant number, since it is smaller than the sum of its proper divisors (18253688330956).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13125435214100 is a wasteful number, since it uses less digits than its factorization.
13125435214100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118140857 (or 118140850 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 13125435214100 its reverse (141253452131), we get a palindrome (13266688666231).
The spelling of 13125435214100 in words is "thirteen trillion, one hundred twenty-five billion, four hundred thirty-five million, two hundred fourteen thousand, one hundred".
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