132114442333140 has 120 divisors (see below), whose sum is σ = 424556384274792. Its totient is φ = 34371237012480.

The previous prime is 132114442333129. The next prime is 132114442333141. The reversal of 132114442333140 is 41333244411231.

132114442333140 is a `hidden beast` number, since 1 + 3 + 2 + 1 + 144 + 42 + 333 + 140 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 555698684304 + 131558743648836 = 745452^2 + 11469906^2 .

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 132114442333095 and 132114442333104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132114442333141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 994471689 + ... + 994604528.

Almost surely, 2^{132114442333140} is an apocalyptic number.

132114442333140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132114442333140 is an abundant number, since it is smaller than the sum of its proper divisors (292441941941652).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132114442333140 is a wasteful number, since it uses less digits than its factorization.

132114442333140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1989076279 (or 1989076268 counting only the distinct ones).

The product of its (nonzero) digits is 82944, while the sum is 36.

Adding to 132114442333140 its reverse (41333244411231), we get a palindrome (173447686744371).

The spelling of 132114442333140 in words is "one hundred thirty-two trillion, one hundred fourteen billion, four hundred forty-two million, three hundred thirty-three thousand, one hundred forty".