Base | Representation |
---|---|
bin | 1100000001000011010010… |
… | …0111010001000000101100 |
3 | 1201210002000002012200022200 |
4 | 3000100310213101000230 |
5 | 3212432042220023040 |
6 | 44033334000141500 |
7 | 2532356453651163 |
oct | 300206447210054 |
9 | 51702002180280 |
10 | 13212202111020 |
11 | 4234299717570 |
12 | 1594743907890 |
13 | 74ab9cc85213 |
14 | 33968c8d63da |
15 | 17da2dea1630 |
hex | c04349d102c |
13212202111020 has 72 divisors (see below), whose sum is σ = 43720377901200. Its totient is φ = 3202958087040.
The previous prime is 13212202111013. The next prime is 13212202111021. The reversal of 13212202111020 is 2011120221231.
13212202111020 is a `hidden beast` number, since 1 + 321 + 220 + 21 + 1 + 102 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 13212202110984 and 13212202111002.
It is not an unprimeable number, because it can be changed into a prime (13212202111021) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3336412695 + ... + 3336416654.
It is an arithmetic number, because the mean of its divisors is an integer number (607227470850).
Almost surely, 213212202111020 is an apocalyptic number.
13212202111020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13212202111020 is an abundant number, since it is smaller than the sum of its proper divisors (30508175790180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13212202111020 is a wasteful number, since it uses less digits than its factorization.
13212202111020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6672829375 (or 6672829370 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 13212202111020 its reverse (2011120221231), we get a palindrome (15223322332251).
It can be divided in two parts, 1321220211 and 1020, that added together give a palindrome (1321221231).
The spelling of 13212202111020 in words is "thirteen trillion, two hundred twelve billion, two hundred two million, one hundred eleven thousand, twenty".
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