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132130010322240 = 2635719662203917
BaseRepresentation
bin11110000010101111101010…
…010101000101010101000000
3122022211111122121012210210220
4132002233222111011111000
5114304304230120302430
61145003404435223040
736555035554545060
oct3602575225052500
9568744577183726
10132130010322240
1139112028228417
121299b821147a80
135895a63b964c8
14248b1ab6433a0
151042011278110
hex782bea545540

132130010322240 has 112 divisors (see below), whose sum is σ = 479443180336512. Its totient is φ = 30201145214976.

The previous prime is 132130010322209. The next prime is 132130010322241. The reversal of 132130010322240 is 42223010031231.

It is a tau number, because it is divible by the number of its divisors (112).

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 132130010322240.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132130010322241) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9831095239 + ... + 9831108678.

It is an arithmetic number, because the mean of its divisors is an integer number (4280742681576).

Almost surely, 2132130010322240 is an apocalyptic number.

132130010322240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132130010322240 is an abundant number, since it is smaller than the sum of its proper divisors (347313170014272).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132130010322240 is a wasteful number, since it uses less digits than its factorization.

132130010322240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19662203944 (or 19662203934 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 132130010322240 its reverse (42223010031231), we get a palindrome (174353020353471).

The spelling of 132130010322240 in words is "one hundred thirty-two trillion, one hundred thirty billion, ten million, three hundred twenty-two thousand, two hundred forty".

Divisors: 1 2 3 4 5 6 7 8 10 12 14 15 16 20 21 24 28 30 32 35 40 42 48 56 60 64 70 80 84 96 105 112 120 140 160 168 192 210 224 240 280 320 336 420 448 480 560 672 840 960 1120 1344 1680 2240 3360 6720 19662203917 39324407834 58986611751 78648815668 98311019585 117973223502 137635427419 157297631336 196622039170 235946447004 275270854838 294933058755 314595262672 393244078340 412906282257 471892894008 550541709676 589866117510 629190525344 688177137095 786488156680 825812564514 943785788016 1101083419352 1179732235020 1258381050688 1376354274190 1572976313360 1651625129028 1887571576032 2064531411285 2202166838704 2359464470040 2752708548380 3145952626720 3303250258056 3775143152064 4129062822570 4404333677408 4718928940080 5505417096760 6291905253440 6606500516112 8258125645140 8808667354816 9437857880160 11010834193520 13213001032224 16516251290280 18875715760320 22021668387040 26426002064448 33032502580560 44043336774080 66065005161120 132130010322240