Base | Representation |
---|---|
bin | 11000100111111101… |
… | …01110001110000000 |
3 | 1021010022222020022100 |
4 | 30103332232032000 |
5 | 204033322024412 |
6 | 10023452510400 |
7 | 645415043226 |
oct | 142376561600 |
9 | 37108866270 |
10 | 13220111232 |
11 | 5674454269 |
12 | 268b47b400 |
13 | 1328b7ac33 |
14 | 8d5aa4b16 |
15 | 52592eedc |
hex | 313fae380 |
13220111232 has 96 divisors (see below), whose sum is σ = 40044537000. Its totient is φ = 4174765056.
The previous prime is 13220111227. The next prime is 13220111237. The reversal of 13220111232 is 23211102231.
13220111232 is a `hidden beast` number, since 1 + 322 + 0 + 111 + 232 = 666.
13220111232 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (13220111227) and next prime (13220111237).
It is a tau number, because it is divible by the number of its divisors (96).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13220111237) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 280107 + ... + 323882.
Almost surely, 213220111232 is an apocalyptic number.
13220111232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13220111232 is an abundant number, since it is smaller than the sum of its proper divisors (26824425768).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13220111232 is a wasteful number, since it uses less digits than its factorization.
13220111232 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 604028 (or 604013 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 13220111232 its reverse (23211102231), we get a palindrome (36431213463).
Subtracting 13220111232 from its reverse (23211102231), we obtain a palindrome (9990990999).
The spelling of 13220111232 in words is "thirteen billion, two hundred twenty million, one hundred eleven thousand, two hundred thirty-two".
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