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132413132114040 = 233510137792891023
BaseRepresentation
bin11110000110110111010101…
…101101000000100001111000
3122100211120102211211000120210
4132012313111231000201320
5114323424043310122130
61145341430401551120
736614350565222361
oct3606672555004170
9570746384730523
10132413132114040
1139211104091018
1212a266760454a0
1358b667400536b
14249ab88d2ab68
151049581cbb5b0
hex786dd5b40878

132413132114040 has 128 divisors (see below), whose sum is σ = 401278756838400. Its totient is φ = 34951299571200.

The previous prime is 132413132113901. The next prime is 132413132114119. The reversal of 132413132114040 is 40411231314231.

It is a super-2 number, since 2×1324131321140402 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 132413132113989 and 132413132114007.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 44355969 + ... + 47246991.

It is an arithmetic number, because the mean of its divisors is an integer number (3134990287800).

Almost surely, 2132413132114040 is an apocalyptic number.

132413132114040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132413132114040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (200639378419200).

132413132114040 is an abundant number, since it is smaller than the sum of its proper divisors (268865624724360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132413132114040 is a wasteful number, since it uses less digits than its factorization.

132413132114040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2894917 (or 2894913 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 132413132114040 its reverse (40411231314231), we get a palindrome (172824363428271).

The spelling of 132413132114040 in words is "one hundred thirty-two trillion, four hundred thirteen billion, one hundred thirty-two million, one hundred fourteen thousand, forty".

Divisors: 1 2 3 4 5 6 8 10 12 15 20 24 30 40 60 101 120 202 303 404 505 606 808 1010 1212 1515 2020 2424 3030 3779 4040 6060 7558 11337 12120 15116 18895 22674 30232 37790 45348 56685 75580 90696 113370 151160 226740 381679 453480 763358 1145037 1526716 1908395 2290074 2891023 3053432 3816790 4580148 5725185 5782046 7633580 8673069 9160296 11450370 11564092 14455115 15267160 17346138 22900740 23128184 28910230 34692276 43365345 45801480 57820460 69384552 86730690 115640920 173461380 291993323 346922760 583986646 875979969 1167973292 1459966615 1751959938 2335946584 2919933230 3503919876 4379899845 5839866460 7007839752 8759799690 10925175917 11679732920 17519599380 21850351834 32775527751 35039198760 43700703668 54625879585 65551055502 87401407336 109251759170 131102111004 163877638755 218503518340 262204222008 327755277510 437007036680 655510555020 1103442767617 1311021110040 2206885535234 3310328302851 4413771070468 5517213838085 6620656605702 8827542140936 11034427676170 13241313211404 16551641514255 22068855352340 26482626422808 33103283028510 44137710704680 66206566057020 132413132114040