Base | Representation |
---|---|
bin | 1100000011011101001001… |
… | …1110000110011101011100 |
3 | 1201221000121120021201110121 |
4 | 3000313102132012131130 |
5 | 3214121134313324200 |
6 | 44104324245044324 |
7 | 2535351133356001 |
oct | 300672236063534 |
9 | 51830546251417 |
10 | 13253505214300 |
11 | 424a8641a236a |
12 | 15a07500b66a4 |
13 | 751a52cbb0c0 |
14 | 33b68a1918a8 |
15 | 17eb4a08ce1a |
hex | c0dd278675c |
13253505214300 has 72 divisors (see below), whose sum is σ = 31086712392512. Its totient is φ = 4875544224000.
The previous prime is 13253505214297. The next prime is 13253505214349. The reversal of 13253505214300 is 341250535231.
13253505214300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18457671 + ... + 19162270.
Almost surely, 213253505214300 is an apocalyptic number.
13253505214300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13253505214300 is an abundant number, since it is smaller than the sum of its proper divisors (17833207178212).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13253505214300 is a wasteful number, since it uses less digits than its factorization.
13253505214300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37620239 (or 37620232 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 13253505214300 its reverse (341250535231), we get a palindrome (13594755749531).
The spelling of 13253505214300 in words is "thirteen trillion, two hundred fifty-three billion, five hundred five million, two hundred fourteen thousand, three hundred".
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