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133101021300 = 223521337922391
BaseRepresentation
bin111101111110101110…
…0000110100001110100
3110201120001001110010120
41323331130012201310
54140042330140200
6141051252451540
712421240004532
oct1737534064164
9421501043116
10133101021300
11514a2069355
1221967319bb0
13c722499690
14662928b152
1536e020e9a0
hex1efd706874

133101021300 has 144 divisors (see below), whose sum is σ = 425938488192. Its totient is φ = 31877798400.

The previous prime is 133101021299. The next prime is 133101021301. The reversal of 133101021300 is 3120101331.

It is an interprime number because it is at equal distance from previous prime (133101021299) and next prime (133101021301).

It is a super-2 number, since 2×1331010213002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 133101021300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133101021301) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 316896 + ... + 605495.

It is an arithmetic number, because the mean of its divisors is an integer number (2957906168).

Almost surely, 2133101021300 is an apocalyptic number.

133101021300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133101021300 is an abundant number, since it is smaller than the sum of its proper divisors (292837466892).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133101021300 is a wasteful number, since it uses less digits than its factorization.

133101021300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 922458 (or 922451 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 133101021300 its reverse (3120101331), we get a palindrome (136221122631).

The spelling of 133101021300 in words is "one hundred thirty-three billion, one hundred one million, twenty-one thousand, three hundred".

Divisors: 1 2 3 4 5 6 10 12 13 15 20 25 26 30 37 39 50 52 60 65 74 75 78 100 111 130 148 150 156 185 195 222 260 300 325 370 390 444 481 555 650 740 780 925 962 975 1110 1300 1443 1850 1924 1950 2220 2405 2775 2886 3700 3900 4810 5550 5772 7215 9620 11100 12025 14430 24050 28860 36075 48100 72150 144300 922391 1844782 2767173 3689564 4611955 5534346 9223910 11068692 11991083 13835865 18447820 23059775 23982166 27671730 34128467 35973249 46119550 47964332 55343460 59955415 68256934 69179325 71946498 92239100 102385401 119910830 136513868 138358650 143892996 170642335 179866245 204770802 239821660 276717300 299777075 341284670 359732490 409541604 443670071 511927005 599554150 682569340 719464980 853211675 887340142 899331225 1023854010 1199108300 1331010213 1706423350 1774680284 1798662450 2047708020 2218350355 2559635025 2662020426 3412846700 3597324900 4436700710 5119270050 5324040852 6655051065 8873401420 10238540100 11091751775 13310102130 22183503550 26620204260 33275255325 44367007100 66550510650 133101021300