Base | Representation |
---|---|
bin | 1100001000101000000110… |
… | …1000111000111010110100 |
3 | 1202020111220212000012112220 |
4 | 3002022001220320322310 |
5 | 3222100104402314030 |
6 | 44213215443442340 |
7 | 2544644464451115 |
oct | 302120150707264 |
9 | 52214825005486 |
10 | 13342343401140 |
11 | 4284502019a96 |
12 | 15b5a039863b0 |
13 | 75a2401c9370 |
14 | 341ab6a6020c |
15 | 1820e9423a10 |
hex | c2281a38eb4 |
13342343401140 has 96 divisors (see below), whose sum is σ = 42349786389120. Its totient is φ = 3111412870656.
The previous prime is 13342343401129. The next prime is 13342343401169. The reversal of 13342343401140 is 4110434324331.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 450131719 + ... + 450161358.
It is an arithmetic number, because the mean of its divisors is an integer number (441143608220).
Almost surely, 213342343401140 is an apocalyptic number.
13342343401140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13342343401140 is an abundant number, since it is smaller than the sum of its proper divisors (29007442987980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13342343401140 is a wasteful number, since it uses less digits than its factorization.
13342343401140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 900293121 (or 900293119 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13342343401140 its reverse (4110434324331), we get a palindrome (17452777725471).
It can be divided in two parts, 1334234 and 3401140, that added together give a palindrome (4735374).
The spelling of 13342343401140 in words is "thirteen trillion, three hundred forty-two billion, three hundred forty-three million, four hundred one thousand, one hundred forty".
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