Base | Representation |
---|---|
bin | 10011100000000000101… |
… | …100011000100100000100 |
3 | 11202002212210100220210020 |
4 | 103200000230120210010 |
5 | 133423401101300200 |
6 | 2503335002255140 |
7 | 165546322141215 |
oct | 23400054304404 |
9 | 4662783326706 |
10 | 1340041431300 |
11 | 4773434a9180 |
12 | 1978611b74b0 |
13 | 99499924b60 |
14 | 48c0345d40c |
15 | 24cce392ea0 |
hex | 13800b18904 |
1340041431300 has 144 divisors (see below), whose sum is σ = 4555016501952. Its totient is φ = 299869401600.
The previous prime is 1340041431247. The next prime is 1340041431317. The reversal of 1340041431300 is 31341400431.
It is a super-2 number, since 2×13400414313002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 15575299 + ... + 15661098.
Almost surely, 21340041431300 is an apocalyptic number.
1340041431300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1340041431300 is an abundant number, since it is smaller than the sum of its proper divisors (3214975070652).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1340041431300 is a wasteful number, since it uses less digits than its factorization.
1340041431300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31236438 (or 31236431 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 1340041431300 its reverse (31341400431), we get a palindrome (1371382831731).
The spelling of 1340041431300 in words is "one trillion, three hundred forty billion, forty-one million, four hundred thirty-one thousand, three hundred".
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