13441011320 has 128 divisors (see below), whose sum is σ = 33555617280. Its totient is φ = 4804800000.

The previous prime is 13441011281. The next prime is 13441011323. The reversal of 13441011320 is 2311014431.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13441011292 and 13441011301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13441011323) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6709439 + ... + 6711441.

It is an arithmetic number, because the mean of its divisors is an integer number (262153260).

Almost surely, 2^13441011320 is an apocalyptic number.

13441011320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13441011320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16777808640).

13441011320 is an abundant number, since it is smaller than the sum of its proper divisors (20114605960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13441011320 is a wasteful number, since it uses less digits than its factorization.

13441011320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2277 (or 2273 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13441011320 its reverse (2311014431), we get a palindrome (15752025751).

The spelling of 13441011320 in words is "thirteen billion, four hundred forty-one million, eleven thousand, three hundred twenty".