13442311040 has 64 divisors (see below), whose sum is σ = 32302326960. Its totient is φ = 5349015552.

The previous prime is 13442311039. The next prime is 13442311049. The reversal of 13442311040 is 4011324431.

It is a tau number, because it is divible by the number of its divisors (64).

It is a super-2 number, since 2×13442311040² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13442310997 and 13442311015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13442311049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69107 + ... + 177933.

Almost surely, 2^13442311040 is an apocalyptic number.

13442311040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13442311040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16151163480).

13442311040 is an abundant number, since it is smaller than the sum of its proper divisors (18860015920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13442311040 is a wasteful number, since it uses less digits than its factorization.

13442311040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 109039 (or 109027 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13442311040 its reverse (4011324431), we get a palindrome (17453635471).

The spelling of 13442311040 in words is "thirteen billion, four hundred forty-two million, three hundred eleven thousand, forty".