13444143242040 has 96 divisors (see below), whose sum is σ = 49935389194080. Its totient is φ = 3072947026176.

The previous prime is 13444143242039. The next prime is 13444143242063. The reversal of 13444143242040 is 4024234144431.

13444143242040 is a `hidden beast` number, since 1 + 3 + 4 + 4 + 414 + 32 + 4 + 204 + 0 = 666.

13444143242040 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 13444143241986 and 13444143242004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2667486219 + ... + 2667491258.

It is an arithmetic number, because the mean of its divisors is an integer number (520160304105).

Almost surely, 2^{13444143242040} is an apocalyptic number.

13444143242040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13444143242040 is an abundant number, since it is smaller than the sum of its proper divisors (36491245952040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13444143242040 is a wasteful number, since it uses less digits than its factorization.

13444143242040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5334977501 (or 5334977494 counting only the distinct ones).

The product of its (nonzero) digits is 147456, while the sum is 36.

Adding to 13444143242040 its reverse (4024234144431), we get a palindrome (17468377386471).

The spelling of 13444143242040 in words is "thirteen trillion, four hundred forty-four billion, one hundred forty-three million, two hundred forty-two thousand, forty".