211130000040 has 128 divisors (see below), whose sum is σ = 645326092800. Its totient is φ = 55250227200.

The previous prime is 211130000027. The next prime is 211130000047. The reversal of 211130000040 is 40000031112.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 211129999980 and 211130000025.

It is not an unprimeable number, because it can be changed into a prime (211130000047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1292481 + ... + 1446639.

It is an arithmetic number, because the mean of its divisors is an integer number (5041610100).

Almost surely, 2^211130000040 is an apocalyptic number.

211130000040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211130000040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (322663046400).

211130000040 is an abundant number, since it is smaller than the sum of its proper divisors (434196092760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211130000040 is a wasteful number, since it uses less digits than its factorization.

211130000040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 154387 (or 154383 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 211130000040 its reverse (40000031112), we get a palindrome (251130031152).

The spelling of 211130000040 in words is "two hundred eleven billion, one hundred thirty million, forty", and thus it is an aban number.