Base | Representation |
---|---|
bin | 1100000001011110111… |
… | …01011011001100011010 |
3 | 1110111022120012000210010 |
4 | 12000233131123030122 |
5 | 23232023423300010 |
6 | 513440451302350 |
7 | 41563220303250 |
oct | 6005735331432 |
9 | 1414276160703 |
10 | 413113103130 |
11 | 14a222638912 |
12 | 680928aa9b6 |
13 | 2cc58290970 |
14 | 15dcd9705d0 |
15 | ab2cc3c620 |
hex | 602f75b31a |
413113103130 has 128 divisors (see below), whose sum is σ = 1225511659008. Its totient is φ = 86788104192.
The previous prime is 413113103129. The next prime is 413113103131. The reversal of 413113103130 is 31301311314.
413113103130 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (413113103129) and next prime (413113103131).
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 413113103097 and 413113103106.
It is not an unprimeable number, because it can be changed into a prime (413113103131) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 311362 + ... + 960818.
It is an arithmetic number, because the mean of its divisors is an integer number (9574309836).
Almost surely, 2413113103130 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 413113103130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (612755829504).
413113103130 is an abundant number, since it is smaller than the sum of its proper divisors (812398555878).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
413113103130 is a wasteful number, since it uses less digits than its factorization.
413113103130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 649720.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 413113103130 its reverse (31301311314), we get a palindrome (444414414444).
The spelling of 413113103130 in words is "four hundred thirteen billion, one hundred thirteen million, one hundred three thousand, one hundred thirty".
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