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413113103130 = 235713233649457
BaseRepresentation
bin1100000001011110111…
…01011011001100011010
31110111022120012000210010
412000233131123030122
523232023423300010
6513440451302350
741563220303250
oct6005735331432
91414276160703
10413113103130
1114a222638912
12680928aa9b6
132cc58290970
1415dcd9705d0
15ab2cc3c620
hex602f75b31a

413113103130 has 128 divisors (see below), whose sum is σ = 1225511659008. Its totient is φ = 86788104192.

The previous prime is 413113103129. The next prime is 413113103131. The reversal of 413113103130 is 31301311314.

413113103130 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (413113103129) and next prime (413113103131).

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a junction number, because it is equal to n+sod(n) for n = 413113103097 and 413113103106.

It is not an unprimeable number, because it can be changed into a prime (413113103131) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 311362 + ... + 960818.

It is an arithmetic number, because the mean of its divisors is an integer number (9574309836).

Almost surely, 2413113103130 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 413113103130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (612755829504).

413113103130 is an abundant number, since it is smaller than the sum of its proper divisors (812398555878).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

413113103130 is a wasteful number, since it uses less digits than its factorization.

413113103130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 649720.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 413113103130 its reverse (31301311314), we get a palindrome (444414414444).

The spelling of 413113103130 in words is "four hundred thirteen billion, one hundred thirteen million, one hundred three thousand, one hundred thirty".

Divisors: 1 2 3 5 6 7 10 13 14 15 21 26 30 35 39 42 65 70 78 91 105 130 182 195 210 233 273 390 455 466 546 699 910 1165 1365 1398 1631 2330 2730 3029 3262 3495 4893 6058 6990 8155 9087 9786 15145 16310 18174 21203 24465 30290 42406 45435 48930 63609 90870 106015 127218 212030 318045 636090 649457 1298914 1948371 3247285 3896742 4546199 6494570 8442941 9092398 9741855 13638597 16885882 19483710 22730995 25328823 27277194 42214705 45461990 50657646 59100587 68192985 84429410 118201174 126644115 136385970 151323481 177301761 253288230 295502935 302646962 354603522 453970443 591005870 756617405 886508805 907940886 1059264367 1513234810 1773017610 1967205253 2118528734 2269852215 3177793101 3934410506 4539704430 5296321835 5901615759 6355586202 9836026265 10592643670 11803231518 13770436771 15888965505 19672052530 27540873542 29508078795 31777931010 41311310313 59016157590 68852183855 82622620626 137704367710 206556551565 413113103130