Base | Representation |
---|---|
bin | 100101001011101110001… |
… | …0110101101011000110100 |
3 | 200002112212110202111110121 |
4 | 1022113130112231120310 |
5 | 1132212111220234130 |
6 | 14511405155301324 |
7 | 1035133541151142 |
oct | 112273426553064 |
9 | 20075773674417 |
10 | 5110413055540 |
11 | 16a034aa3a391 |
12 | 6a6522baa844 |
13 | 2b0baa024020 |
14 | 1394b976c592 |
15 | 8ce00c0ad7a |
hex | 4a5dc5ad634 |
5110413055540 has 96 divisors (see below), whose sum is σ = 12079012409856. Its totient is φ = 1802019985920.
The previous prime is 5110413055529. The next prime is 5110413055541. The reversal of 5110413055540 is 455503140115.
It is a super-3 number, since 3×51104130555403 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 5110413055496 and 5110413055505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5110413055541) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3096214 + ... + 4450546.
It is an arithmetic number, because the mean of its divisors is an integer number (125823045936).
Almost surely, 25110413055540 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 5110413055540, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6039506204928).
5110413055540 is an abundant number, since it is smaller than the sum of its proper divisors (6968599354316).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5110413055540 is a wasteful number, since it uses less digits than its factorization.
5110413055540 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1355009 (or 1355007 counting only the distinct ones).
The product of its (nonzero) digits is 30000, while the sum is 34.
Adding to 5110413055540 its reverse (455503140115), we get a palindrome (5565916195655).
The spelling of 5110413055540 in words is "five trillion, one hundred ten billion, four hundred thirteen million, fifty-five thousand, five hundred forty".
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