Base | Representation |
---|---|
bin | 101000000010000110100… |
… | …1001011111110001000011 |
3 | 201110222210222100200110000 |
4 | 1100010031021133301003 |
5 | 1210121221331340040 |
6 | 15411341234211043 |
7 | 1105340341535400 |
oct | 120041511376103 |
9 | 21428728320400 |
10 | 5502073699395 |
11 | 183146418a009 |
12 | 74a409423a83 |
13 | 30bac6a219b0 |
14 | 15043216b2a7 |
15 | 981c5424130 |
hex | 5010d25fc43 |
5502073699395 has 120 divisors (see below), whose sum is σ = 12355817365584. Its totient is φ = 2321754067584.
The previous prime is 5502073699391. The next prime is 5502073699469. The reversal of 5502073699395 is 5939963702055.
5502073699395 is a `hidden beast` number, since 5 + 5 + 0 + 207 + 36 + 9 + 9 + 395 = 666.
It is not a de Polignac number, because 5502073699395 - 22 = 5502073699391 is a prime.
It is a super-4 number, since 4×55020736993954 (a number of 52 digits) contains 4444 as substring.
It is a Harshad number since it is a multiple of its sum of digits (63).
It is not an unprimeable number, because it can be changed into a prime (5502073699391) by changing a digit.
It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 10405569 + ... + 10921538.
Almost surely, 25502073699395 is an apocalyptic number.
5502073699395 is an abundant number, since it is smaller than the sum of its proper divisors (6853743666189).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5502073699395 is a wasteful number, since it uses less digits than its factorization.
5502073699395 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21327151 (or 21327135 counting only the distinct ones).
The product of its (nonzero) digits is 68890500, while the sum is 63.
The spelling of 5502073699395 in words is "five trillion, five hundred two billion, seventy-three million, six hundred ninety-nine thousand, three hundred ninety-five".
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