Base | Representation |
---|---|
bin | 110101001101001101… |
… | …101101110100000000 |
3 | 12110110111012111211112 |
4 | 311031031231310000 |
5 | 1414000241003000 |
6 | 42124542302452 |
7 | 4061510060261 |
oct | 651515556400 |
9 | 173414174745 |
10 | 57130016000 |
11 | 2225744a662 |
12 | b0a4887a28 |
13 | 5505c987c5 |
14 | 2a9d652968 |
15 | 17457e2235 |
hex | d4d36dd00 |
57130016000 has 72 divisors (see below), whose sum is σ = 142318090824. Its totient is φ = 22851993600.
The previous prime is 57130015991. The next prime is 57130016003. The reversal of 57130016000 is 61003175.
It can be written as a sum of positive squares in 4 ways, for example, as 7261766656 + 49868249344 = 85216^2 + 223312^2 .
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (57130016003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 860657 + ... + 924656.
Almost surely, 257130016000 is an apocalyptic number.
57130016000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
57130016000 is an abundant number, since it is smaller than the sum of its proper divisors (85188074824).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
57130016000 is an equidigital number, since it uses as much as digits as its factorization.
57130016000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1785344 (or 1785320 counting only the distinct ones).
The product of its (nonzero) digits is 630, while the sum is 23.
Adding to 57130016000 its reverse (61003175), we get a palindrome (57191019175).
The spelling of 57130016000 in words is "fifty-seven billion, one hundred thirty million, sixteen thousand".
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