Base | Representation |
---|---|
bin | 101110101000001101… |
… | …0001110101110000000 |
3 | 100120110110110202000020 |
4 | 1131100122032232000 |
5 | 3120033111113440 |
6 | 114000044053440 |
7 | 10143253005336 |
oct | 1352032165600 |
9 | 316413422006 |
10 | 100133301120 |
11 | 39514702216 |
12 | 174a6534280 |
13 | 959a312948 |
14 | 4bbca3db56 |
15 | 2910cbb3d0 |
hex | 175068eb80 |
100133301120 has 128 divisors (see below), whose sum is σ = 319904640000. Its totient is φ = 26641164288.
The previous prime is 100133301113. The next prime is 100133301131. The reversal of 100133301120 is 21103331001.
It is a tau number, because it is divible by the number of its divisors (128).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 100133301120.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 783481 + ... + 902279.
It is an arithmetic number, because the mean of its divisors is an integer number (2499255000).
Almost surely, 2100133301120 is an apocalyptic number.
100133301120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 100133301120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (159952320000).
100133301120 is an abundant number, since it is smaller than the sum of its proper divisors (219771338880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100133301120 is a wasteful number, since it uses less digits than its factorization.
100133301120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 119260 (or 119248 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 100133301120 its reverse (21103331001), we get a palindrome (121236632121).
It can be divided in two parts, 10013 and 3301120, that added together give a palindrome (3311133).
The spelling of 100133301120 in words is "one hundred billion, one hundred thirty-three million, three hundred one thousand, one hundred twenty".
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