1011321300 has 144 divisors (see below), whose sum is σ = 3266790912. Its totient is φ = 239433600.

The previous prime is 1011321287. The next prime is 1011321317. The reversal of 1011321300 is 31231101.

1011321300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 138337 + ... + 145463.

It is an arithmetic number, because the mean of its divisors is an integer number (22686048).

Almost surely, 2^1011321300 is an apocalyptic number.

1011321300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1011321300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1633395456).

1011321300 is an abundant number, since it is smaller than the sum of its proper divisors (2255469612).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011321300 is a wasteful number, since it uses less digits than its factorization.

1011321300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7198 (or 7191 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

The square root of 1011321300 is about 31801.2782761951. The cubic root of 1011321300 is about 1003.7596142537.

Adding to 1011321300 its reverse (31231101), we get a palindrome (1042552401).

It can be divided in two parts, 10113 and 21300, that added together give a palindrome (31413).

The spelling of 1011321300 in words is "one billion, eleven million, three hundred twenty-one thousand, three hundred".