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11000200312320 = 29351432317749
BaseRepresentation
bin1010000000010010111100…
…0010000011011000000000
31102221121102212120121011020
42200010233002003120000
52420211402234443240
635221231112545440
72213511134621262
oct240045702033000
942847385517136
1011000200312320
11356118233558a
121297ab49b2280
1361a411a8a55b
142a05abdd9b32
151412190760d0
hexa012f083600

11000200312320 has 80 divisors (see below), whose sum is σ = 35166265398000. Its totient is φ = 2933386747904.

The previous prime is 11000200312301. The next prime is 11000200312333. The reversal of 11000200312320 is 2321300200011.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×110002003123202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 11000200312320.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 716151195 + ... + 716166554.

It is an arithmetic number, because the mean of its divisors is an integer number (439578317475).

Almost surely, 211000200312320 is an apocalyptic number.

11000200312320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11000200312320 is an abundant number, since it is smaller than the sum of its proper divisors (24166065085680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11000200312320 is an equidigital number, since it uses as much as digits as its factorization.

11000200312320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1432317775 (or 1432317759 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 11000200312320 its reverse (2321300200011), we get a palindrome (13321500512331).

The spelling of 11000200312320 in words is "eleven trillion, two hundred million, three hundred twelve thousand, three hundred twenty".

Divisors: 1 2 3 4 5 6 8 10 12 15 16 20 24 30 32 40 48 60 64 80 96 120 128 160 192 240 256 320 384 480 512 640 768 960 1280 1536 1920 2560 3840 7680 1432317749 2864635498 4296953247 5729270996 7161588745 8593906494 11458541992 14323177490 17187812988 21484766235 22917083984 28646354980 34375625976 42969532470 45834167968 57292709960 68751251952 85939064940 91668335936 114585419920 137502503904 171878129880 183336671872 229170839840 275005007808 343756259760 366673343744 458341679680 550010015616 687512519520 733346687488 916683359360 1100020031232 1375025039040 1833366718720 2200040062464 2750050078080 3666733437440 5500100156160 11000200312320