Base | Representation |
---|---|
bin | 100001011000011… |
… | …1101101110110100 |
3 | 2220001201121021010 |
4 | 1002300331232310 |
5 | 4243223211040 |
6 | 303052152220 |
7 | 36520652010 |
oct | 10260755664 |
9 | 2801647233 |
10 | 1120132020 |
11 | 525315847 |
12 | 273168670 |
13 | 14b0ac217 |
14 | a8a9d540 |
15 | 68510e80 |
hex | 42c3dbb4 |
1120132020 has 96 divisors (see below), whose sum is σ = 3643266816. Its totient is φ = 251827200.
The previous prime is 1120132019. The next prime is 1120132037. The reversal of 1120132020 is 202310211.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a junction number, because it is equal to n+sod(n) for n = 1120131987 and 1120132005.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3760 + ... + 47480.
It is an arithmetic number, because the mean of its divisors is an integer number (37950696).
Almost surely, 21120132020 is an apocalyptic number.
1120132020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1120132020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1821633408).
1120132020 is an abundant number, since it is smaller than the sum of its proper divisors (2523134796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1120132020 is a wasteful number, since it uses less digits than its factorization.
1120132020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43801 (or 43799 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 12.
The square root of 1120132020 is about 33468.3734292541. The cubic root of 1120132020 is about 1038.5396231165.
Adding to 1120132020 its reverse (202310211), we get a palindrome (1322442231).
The spelling of 1120132020 in words is "one billion, one hundred twenty million, one hundred thirty-two thousand, twenty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •