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113124424032 = 25322938934819
BaseRepresentation
bin110100101011010111…
…1011011100101100000
3101210222211120011101200
41221112233123211200
53323134323032112
6123545121001200
711113220511264
oct1512657334540
9353884504350
10113124424032
1143a80874134
1219b11183200
13a88a8c6c19
1456921380a4
152e21567cdc
hex1a56bdb960

113124424032 has 144 divisors (see below), whose sum is σ = 333655686000. Its totient is φ = 36313224192.

The previous prime is 113124424009. The next prime is 113124424067. The reversal of 113124424032 is 230424421311.

113124424032 is a `hidden beast` number, since 1 + 13 + 1 + 244 + 2 + 403 + 2 = 666.

It is a tau number, because it is divible by the number of its divisors (144).

It is a junction number, because it is equal to n+sod(n) for n = 113124423987 and 113124424005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3231519 + ... + 3266337.

It is an arithmetic number, because the mean of its divisors is an integer number (2317053375).

Almost surely, 2113124424032 is an apocalyptic number.

113124424032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113124424032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (166827843000).

113124424032 is an abundant number, since it is smaller than the sum of its proper divisors (220531261968).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113124424032 is a wasteful number, since it uses less digits than its factorization.

113124424032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35253 (or 35242 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 113124424032 its reverse (230424421311), we get a palindrome (343548845343).

It can be divided in two parts, 11312 and 4424032, that added together give a palindrome (4435344).

The spelling of 113124424032 in words is "one hundred thirteen billion, one hundred twenty-four million, four hundred twenty-four thousand, thirty-two".

Divisors: 1 2 3 4 6 8 9 12 16 18 24 29 32 36 48 58 72 87 96 116 144 174 232 261 288 348 389 464 522 696 778 928 1044 1167 1392 1556 2088 2334 2784 3112 3501 4176 4668 6224 7002 8352 9336 11281 12448 14004 18672 22562 28008 33843 34819 37344 45124 56016 67686 69638 90248 101529 104457 112032 135372 139276 180496 203058 208914 270744 278552 313371 360992 406116 417828 541488 557104 626742 812232 835656 1009751 1082976 1114208 1253484 1624464 1671312 2019502 2506968 3029253 3248928 3342624 4039004 5013936 6058506 8078008 9087759 10027872 12117012 13544591 16156016 18175518 24234024 27089182 32312032 36351036 40633773 48468048 54178364 72702072 81267546 96936096 108356728 121901319 145404144 162535092 216713456 243802638 290808288 325070184 392793139 433426912 487605276 650140368 785586278 975210552 1178379417 1300280736 1571172556 1950421104 2356758834 3142345112 3535138251 3900842208 4713517668 6284690224 7070276502 9427035336 12569380448 14140553004 18854070672 28281106008 37708141344 56562212016 113124424032