Base | Representation |
---|---|
bin | 110100101011010111… |
… | …1011011100101100000 |
3 | 101210222211120011101200 |
4 | 1221112233123211200 |
5 | 3323134323032112 |
6 | 123545121001200 |
7 | 11113220511264 |
oct | 1512657334540 |
9 | 353884504350 |
10 | 113124424032 |
11 | 43a80874134 |
12 | 19b11183200 |
13 | a88a8c6c19 |
14 | 56921380a4 |
15 | 2e21567cdc |
hex | 1a56bdb960 |
113124424032 has 144 divisors (see below), whose sum is σ = 333655686000. Its totient is φ = 36313224192.
The previous prime is 113124424009. The next prime is 113124424067. The reversal of 113124424032 is 230424421311.
113124424032 is a `hidden beast` number, since 1 + 13 + 1 + 244 + 2 + 403 + 2 = 666.
It is a tau number, because it is divible by the number of its divisors (144).
It is a junction number, because it is equal to n+sod(n) for n = 113124423987 and 113124424005.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3231519 + ... + 3266337.
It is an arithmetic number, because the mean of its divisors is an integer number (2317053375).
Almost surely, 2113124424032 is an apocalyptic number.
113124424032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113124424032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (166827843000).
113124424032 is an abundant number, since it is smaller than the sum of its proper divisors (220531261968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113124424032 is a wasteful number, since it uses less digits than its factorization.
113124424032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35253 (or 35242 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 113124424032 its reverse (230424421311), we get a palindrome (343548845343).
It can be divided in two parts, 11312 and 4424032, that added together give a palindrome (4435344).
The spelling of 113124424032 in words is "one hundred thirteen billion, one hundred twenty-four million, four hundred twenty-four thousand, thirty-two".
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