Base | Representation |
---|---|
bin | 1010010011101011111010… |
… | …0101000101111000010100 |
3 | 1111010110021122011001101020 |
4 | 2210322332211011320110 |
5 | 2441141120201340200 |
6 | 40034242244001140 |
7 | 2246543156026143 |
oct | 244727645057024 |
9 | 44113248131336 |
10 | 11333321121300 |
11 | 367a48634a892 |
12 | 13305823901b0 |
13 | 64295c6b3989 |
14 | 2b276dc3975a |
15 | 149c14317ea0 |
hex | a4ebe945e14 |
11333321121300 has 144 divisors (see below), whose sum is σ = 32924994665472. Its totient is φ = 3009887971200.
The previous prime is 11333321121281. The next prime is 11333321121307. The reversal of 11333321121300 is 312112333311.
11333321121300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11333321121307) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 158812227 + ... + 158883573.
It is an arithmetic number, because the mean of its divisors is an integer number (228645796288).
Almost surely, 211333321121300 is an apocalyptic number.
11333321121300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11333321121300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16462497332736).
11333321121300 is an abundant number, since it is smaller than the sum of its proper divisors (21591673544172).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11333321121300 is a wasteful number, since it uses less digits than its factorization.
11333321121300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73518 (or 73511 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 11333321121300 its reverse (312112333311), we get a palindrome (11645433454611).
The spelling of 11333321121300 in words is "eleven trillion, three hundred thirty-three billion, three hundred twenty-one million, one hundred twenty-one thousand, three hundred".
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