Base | Representation |
---|---|
bin | 110101001000110101… |
… | …1011001011100000000 |
3 | 101220112202011022202110 |
4 | 1222101223121130000 |
5 | 3332200441104100 |
6 | 124231202215320 |
7 | 11146555246332 |
oct | 1522153313400 |
9 | 356482138673 |
10 | 114113222400 |
11 | 44438a36a71 |
12 | 1a148354540 |
13 | a9b7711608 |
14 | 57475ab452 |
15 | 2e7d285250 |
hex | 1a91ad9700 |
114113222400 has 108 divisors (see below), whose sum is σ = 376597470872. Its totient is φ = 30430187520.
The previous prime is 114113222393. The next prime is 114113222417. The reversal of 114113222400 is 4222311411.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2952499 + ... + 2990898.
Almost surely, 2114113222400 is an apocalyptic number.
114113222400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
114113222400 is an abundant number, since it is smaller than the sum of its proper divisors (262484248472).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114113222400 is an equidigital number, since it uses as much as digits as its factorization.
114113222400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5943426 (or 5943407 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 114113222400 its reverse (4222311411), we get a palindrome (118335533811).
The spelling of 114113222400 in words is "one hundred fourteen billion, one hundred thirteen million, two hundred twenty-two thousand, four hundred".
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