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12012132 = 223111753101
BaseRepresentation
bin101101110100…
…101001100100
3211121021112210
4231310221210
511033342012
61105243420
7204046536
oct55645144
924537483
1012012132
116864990
124033570
132647692
141849856
1510c423c
hexb74a64

12012132 has 96 divisors (see below), whose sum is σ = 33312384. Its totient is φ = 3328000.

The previous prime is 12012131. The next prime is 12012137. The reversal of 12012132 is 23121021.

Added to its reverse (23121021) it gives a triangular number (35133153 = T8382).

12012132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012131) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 118882 + ... + 118982.

It is an arithmetic number, because the mean of its divisors is an integer number (347004).

Almost surely, 212012132 is an apocalyptic number.

12012132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12012132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16656192).

12012132 is an abundant number, since it is smaller than the sum of its proper divisors (21300252).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12012132 is a wasteful number, since it uses less digits than its factorization.

12012132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 189 (or 187 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

The square root of 12012132 is about 3465.8522761364. The cubic root of 12012132 is about 229.0199762644.

Adding to 12012132 its reverse (23121021), we get a palindrome (35133153).

Subtracting 12012132 from its reverse (23121021), we obtain a square (11108889 = 33332).

It can be divided in two parts, 1201 and 2132, that added together give a palindrome (3333).

The spelling of 12012132 in words is "twelve million, twelve thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 11 12 17 22 33 34 44 51 53 66 68 101 102 106 132 159 187 202 204 212 303 318 374 404 561 583 606 636 748 901 1111 1122 1166 1212 1717 1749 1802 2222 2244 2332 2703 3333 3434 3498 3604 4444 5151 5353 5406 6666 6868 6996 9911 10302 10706 10812 13332 16059 18887 19822 20604 21412 29733 32118 37774 39644 56661 58883 59466 64236 75548 91001 113322 117766 118932 176649 182002 226644 235532 273003 353298 364004 546006 706596 1001011 1092012 2002022 3003033 4004044 6006066 12012132