13000040111100 has 144 divisors (see below), whose sum is σ = 43715389536000. Its totient is φ = 2921074360320.

The previous prime is 13000040111099. The next prime is 13000040111101. The reversal of 13000040111100 is 111104000031.

It is an interprime number because it is at equal distance from previous prime (13000040111099) and next prime (13000040111101).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000040111101) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 52337925 + ... + 52585724.

It is an arithmetic number, because the mean of its divisors is an integer number (303579094000).

Almost surely, 2^{13000040111100} is an apocalyptic number.

13000040111100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13000040111100 is an abundant number, since it is smaller than the sum of its proper divisors (30715349424900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13000040111100 is a wasteful number, since it uses less digits than its factorization.

13000040111100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104923732 (or 104923725 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 13000040111100 its reverse (111104000031), we get a palindrome (13111144111131).

The spelling of 13000040111100 in words is "thirteen trillion, forty million, one hundred eleven thousand, one hundred".