130034343040 has 128 divisors (see below), whose sum is σ = 355609699200. Its totient is φ = 44540878848.

The previous prime is 130034343007. The next prime is 130034343041. The reversal of 130034343040 is 40343430031.

130034343040 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (128).

It is a junction number, because it is equal to n+sod(n) for n = 130034342996 and 130034343014.

It is not an unprimeable number, because it can be changed into a prime (130034343041) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4901331 + ... + 4927789.

It is an arithmetic number, because the mean of its divisors is an integer number (2778200775).

Almost surely, 2^130034343040 is an apocalyptic number.

130034343040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130034343040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (177804849600).

130034343040 is an abundant number, since it is smaller than the sum of its proper divisors (225575356160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130034343040 is a wasteful number, since it uses less digits than its factorization.

130034343040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27582 (or 27570 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 130034343040 its reverse (40343430031), we get a palindrome (170377773071).

The spelling of 130034343040 in words is "one hundred thirty billion, thirty-four million, three hundred forty-three thousand, forty".