13004014021110 has 128 divisors (see below), whose sum is σ = 40997876889600. Its totient is φ = 2869851358080.

The previous prime is 13004014021109. The next prime is 13004014021111. The reversal of 13004014021110 is 1112041040031.

13004014021110 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 401 + 40 + 211 + 10 = 666.

It is an interprime number because it is at equal distance from previous prime (13004014021109) and next prime (13004014021111).

It is a super-2 number, since 2×13004014021110² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004014021111) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 118573306 + ... + 118682925.

It is an arithmetic number, because the mean of its divisors is an integer number (320295913200).

Almost surely, 2^{13004014021110} is an apocalyptic number.

13004014021110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13004014021110 is an abundant number, since it is smaller than the sum of its proper divisors (27993862868490).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13004014021110 is a wasteful number, since it uses less digits than its factorization.

13004014021110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 237256283 (or 237256277 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 13004014021110 its reverse (1112041040031), we get a palindrome (14116055061141).

The spelling of 13004014021110 in words is "thirteen trillion, four billion, fourteen million, twenty-one thousand, one hundred ten".