Base | Representation |
---|---|
bin | 111100101001011101… |
… | …0001110001000000000 |
3 | 110110011122120011021210 |
4 | 1321102322032020000 |
5 | 4113212420402200 |
6 | 135455331250120 |
7 | 12260316562062 |
oct | 1712272161000 |
9 | 413148504253 |
10 | 130240012800 |
11 | 50264101317 |
12 | 212a9149940 |
13 | c38782b441 |
14 | 6437305732 |
15 | 35c3e73650 |
hex | 1e52e8e200 |
130240012800 has 120 divisors (see below), whose sum is σ = 430239869136. Its totient is φ = 34730659840.
The previous prime is 130240012787. The next prime is 130240012811. The reversal of 130240012800 is 8210042031.
It is a tau number, because it is divible by the number of its divisors (120).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1657434 + ... + 1734233.
Almost surely, 2130240012800 is an apocalyptic number.
130240012800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130240012800 is an abundant number, since it is smaller than the sum of its proper divisors (299999856336).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130240012800 is an equidigital number, since it uses as much as digits as its factorization.
130240012800 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3391698 (or 3391677 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 130240012800 its reverse (8210042031), we get a palindrome (138450054831).
The spelling of 130240012800 in words is "one hundred thirty billion, two hundred forty million, twelve thousand, eight hundred".
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