13044012000 has 96 divisors (see below), whose sum is σ = 42732222624. Its totient is φ = 3478400000.

The previous prime is 13044011983. The next prime is 13044012017. The reversal of 13044012000 is 21044031.

It is an interprime number because it is at equal distance from previous prime (13044011983) and next prime (13044012017).

It is a tau number, because it is divible by the number of its divisors (96).

It is a super-2 number, since 2×13044012000² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 531501 + ... + 555500.

It is an arithmetic number, because the mean of its divisors is an integer number (445127319).

Almost surely, 2^13044012000 is an apocalyptic number.

13044012000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13044012000 is an abundant number, since it is smaller than the sum of its proper divisors (29688210624).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13044012000 is a wasteful number, since it uses less digits than its factorization.

13044012000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1087029 (or 1087011 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 13044012000 its reverse (21044031), we get a palindrome (13065056031).

The spelling of 13044012000 in words is "thirteen billion, forty-four million, twelve thousand".