13100114400 has 144 divisors (see below), whose sum is σ = 42903753984. Its totient is φ = 3471828480.

The previous prime is 13100114399. The next prime is 13100114413. The reversal of 13100114400 is 441100131.

It is a super-2 number, since 2×13100114400² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13100114400.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 374457 + ... + 407943.

It is an arithmetic number, because the mean of its divisors is an integer number (297942736).

Almost surely, 2^13100114400 is an apocalyptic number.

13100114400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13100114400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21451876992).

13100114400 is an abundant number, since it is smaller than the sum of its proper divisors (29803639584).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100114400 is a wasteful number, since it uses less digits than its factorization.

13100114400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33673 (or 33660 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 13100114400 its reverse (441100131), we get a palindrome (13541214531).

The spelling of 13100114400 in words is "thirteen billion, one hundred million, one hundred fourteen thousand, four hundred".