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13104444335550 = 2352413347636631
BaseRepresentation
bin1011111010110001110110…
…1111111110010110111110
31201101202212020221111202120
42332230131233332112332
53204200400222214200
643512033145103410
72521523226661401
oct276543557762676
951352766844676
1013104444335550
1141a2622216987
12157788ba87b66
13740989181bb9
14334389421d38
1517ad23b669a0
hexbeb1dbfe5be

13104444335550 has 96 divisors (see below), whose sum is σ = 33301680056064. Its totient is φ = 3408262368000.

The previous prime is 13104444335501. The next prime is 13104444335551. The reversal of 13104444335550 is 5553344440131.

It is a super-2 number, since 2×131044443355502 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104444335551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 20265735 + ... + 20902365.

It is an arithmetic number, because the mean of its divisors is an integer number (346892500584).

Almost surely, 213104444335550 is an apocalyptic number.

13104444335550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13104444335550, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16650840028032).

13104444335550 is an abundant number, since it is smaller than the sum of its proper divisors (20197235720514).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104444335550 is a wasteful number, since it uses less digits than its factorization.

13104444335550 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 640034 (or 640029 counting only the distinct ones).

The product of its (nonzero) digits is 864000, while the sum is 42.

Adding to 13104444335550 its reverse (5553344440131), we get a palindrome (18657788775681).

The spelling of 13104444335550 in words is "thirteen trillion, one hundred four billion, four hundred forty-four million, three hundred thirty-five thousand, five hundred fifty".

Divisors: 1 2 3 5 6 10 15 25 30 41 50 75 82 123 150 205 246 410 615 1025 1230 2050 3075 3347 6150 6694 10041 16735 20082 33470 50205 83675 100410 137227 167350 251025 274454 411681 502050 636631 686135 823362 1273262 1372270 1909893 2058405 3183155 3430675 3819786 4116810 6366310 6861350 9549465 10292025 15915775 19098930 20584050 26101871 31831550 47747325 52203742 78305613 95494650 130509355 156611226 261018710 391528065 652546775 783056130 1305093550 1957640325 2130803957 3915280650 4261607914 6392411871 10654019785 12784823742 21308039570 31962059355 53270098925 63924118710 87362962237 106540197850 159810296775 174725924474 262088886711 319620593550 436814811185 524177773422 873629622370 1310444433555 2184074055925 2620888867110 4368148111850 6552222167775 13104444335550