131052240125040 has 120 divisors (see below), whose sum is σ = 439916780153520. Its totient is φ = 32259012943872.

The previous prime is 131052240124961. The next prime is 131052240125089. The reversal of 131052240125040 is 40521042250131.

It is a tau number, because it is divible by the number of its divisors (120).

It is a super-2 number, since 2×131052240125040² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 131052240124989 and 131052240125007.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1615494945 + ... + 1615576064.

It is an arithmetic number, because the mean of its divisors is an integer number (3665973167946).

Almost surely, 2^{131052240125040} is an apocalyptic number.

131052240125040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131052240125040 is an abundant number, since it is smaller than the sum of its proper divisors (308864540028480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131052240125040 is a wasteful number, since it uses less digits than its factorization.

131052240125040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3231071051 (or 3231071032 counting only the distinct ones).

The product of its (nonzero) digits is 9600, while the sum is 30.

Adding to 131052240125040 its reverse (40521042250131), we get a palindrome (171573282375171).

The spelling of 131052240125040 in words is "one hundred thirty-one trillion, fifty-two billion, two hundred forty million, one hundred twenty-five thousand, forty".