Base | Representation |
---|---|
bin | 1011111011001011011100… |
… | …0000000111110111011100 |
3 | 1201102102120202202021021221 |
4 | 2332302313000013313130 |
5 | 3204303430433401030 |
6 | 43515130341503124 |
7 | 2522155331665240 |
oct | 276626700076734 |
9 | 51372522667257 |
10 | 13111310450140 |
11 | 41a5525a35451 |
12 | 1579087411aa4 |
13 | 74151180b9b6 |
14 | 33483b28a420 |
15 | 17b0c6835e7a |
hex | becb7007ddc |
13111310450140 has 96 divisors (see below), whose sum is σ = 33197084928000. Its totient is φ = 4249226096640.
The previous prime is 13111310450107. The next prime is 13111310450153. The reversal of 13111310450140 is 4105401311131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4294596 + ... + 6683275.
It is an arithmetic number, because the mean of its divisors is an integer number (345802968000).
Almost surely, 213111310450140 is an apocalyptic number.
13111310450140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13111310450140 is an abundant number, since it is smaller than the sum of its proper divisors (20085774477860).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111310450140 is a wasteful number, since it uses less digits than its factorization.
13111310450140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10978355 (or 10978353 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 13111310450140 its reverse (4105401311131), we get a palindrome (17216711761271).
The spelling of 13111310450140 in words is "thirteen trillion, one hundred eleven billion, three hundred ten million, four hundred fifty thousand, one hundred forty".
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