Base | Representation |
---|---|
bin | 1011111011001011011111… |
… | …0000000111111011010100 |
3 | 1201102102121122102120010220 |
4 | 2332302313300013323110 |
5 | 3204303442144031200 |
6 | 43515131511314340 |
7 | 2522155543643652 |
oct | 276626760077324 |
9 | 51372548376126 |
10 | 13111323033300 |
11 | 41a553204a358 |
12 | 157908b67b9b0 |
13 | 7415142c625b |
14 | 33483cc03dd2 |
15 | 17b0c79be4a0 |
hex | becb7c07ed4 |
13111323033300 has 144 divisors (see below), whose sum is σ = 39161309182464. Its totient is φ = 3383380800000.
The previous prime is 13111323033299. The next prime is 13111323033317. The reversal of 13111323033300 is 333032311131.
It is a super-2 number, since 2×131113230333002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 268754910 + ... + 268803690.
Almost surely, 213111323033300 is an apocalyptic number.
13111323033300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13111323033300 is an abundant number, since it is smaller than the sum of its proper divisors (26049986149164).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111323033300 is a wasteful number, since it uses less digits than its factorization.
13111323033300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77730 (or 77723 counting only the distinct ones).
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 13111323033300 its reverse (333032311131), we get a palindrome (13444355344431).
The spelling of 13111323033300 in words is "thirteen trillion, one hundred eleven billion, three hundred twenty-three million, thirty-three thousand, three hundred".
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