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13200043304000 = 26537235715059
BaseRepresentation
bin1100000000010101111111…
…1001000110010001000000
31201201220121201021021200202
43000011133321012101000
53212232142041212000
644024003254504332
72531446243544210
oct300053771062100
951656551237622
1013200043304000
11422a11a358923
12159230b9650a8
137499b2c59c57
14338c57b7a240
1517d56b811dd5
hexc015fe46440

13200043304000 has 112 divisors (see below), whose sum is σ = 37359894149760. Its totient is φ = 4525729113600.

The previous prime is 13200043303939. The next prime is 13200043304009. The reversal of 13200043304000 is 40334000231.

It is a tau number, because it is divible by the number of its divisors (112).

It is a super-2 number, since 2×132000433040002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (13200043304009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 117801530 + ... + 117913529.

It is an arithmetic number, because the mean of its divisors is an integer number (333570483480).

Almost surely, 213200043304000 is an apocalyptic number.

13200043304000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13200043304000 is an abundant number, since it is smaller than the sum of its proper divisors (24159850845760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13200043304000 is an equidigital number, since it uses as much as digits as its factorization.

13200043304000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 235715093 (or 235715073 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 20.

Adding to 13200043304000 its reverse (40334000231), we get a palindrome (13240377304231).

The spelling of 13200043304000 in words is "thirteen trillion, two hundred billion, forty-three million, three hundred four thousand".

Divisors: 1 2 4 5 7 8 10 14 16 20 25 28 32 35 40 50 56 64 70 80 100 112 125 140 160 175 200 224 250 280 320 350 400 448 500 560 700 800 875 1000 1120 1400 1600 1750 2000 2240 2800 3500 4000 5600 7000 8000 11200 14000 28000 56000 235715059 471430118 942860236 1178575295 1650005413 1885720472 2357150590 3300010826 3771440944 4714301180 5892876475 6600021652 7542881888 8250027065 9428602360 11785752950 13200043304 15085763776 16500054130 18857204720 23571505900 26400086608 29464382375 33000108260 37714409440 41250135325 47143011800 52800173216 58928764750 66000216520 75428818880 82500270650 94286023600 105600346432 117857529500 132000433040 165000541300 188572047200 206250676625 235715059000 264000866080 330001082600 377144094400 412501353250 471430118000 528001732160 660002165200 825002706500 942860236000 1320004330400 1650005413000 1885720472000 2640008660800 3300010826000 6600021652000 13200043304000