Base | Representation |
---|---|
bin | 1100101101010001110001… |
… | …1000010001011000000000 |
3 | 1211110201012000220022200201 |
4 | 3023110130120101120000 |
5 | 3312404131203113220 |
6 | 45414352251254544 |
7 | 2641305205510411 |
oct | 313243430213000 |
9 | 54421160808621 |
10 | 13972004738560 |
11 | 44a7548475390 |
12 | 1697a5014a454 |
13 | 7a4729004cab |
14 | 36436a393808 |
15 | 19369d2c0d0a |
hex | cb51c611600 |
13972004738560 has 160 divisors (see below), whose sum is σ = 38695262978592. Its totient is φ = 4781862420480.
The previous prime is 13972004738537. The next prime is 13972004738597. The reversal of 13972004738560 is 6583740027931.
It is a tau number, because it is divible by the number of its divisors (160).
It is a Harshad number since it is a multiple of its sum of digits (55).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14114367 + ... + 15071806.
It is a 1-persistent number, because it is pandigital, but 2⋅13972004738560 = 27944009477120 is not.
Almost surely, 213972004738560 is an apocalyptic number.
13972004738560 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13972004738560 is an abundant number, since it is smaller than the sum of its proper divisors (24723258240032).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13972004738560 is a wasteful number, since it uses less digits than its factorization.
13972004738560 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29186224 (or 29186208 counting only the distinct ones).
The product of its (nonzero) digits is 7620480, while the sum is 55.
The spelling of 13972004738560 in words is "thirteen trillion, nine hundred seventy-two billion, four million, seven hundred thirty-eight thousand, five hundred sixty".
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