Base | Representation |
---|---|
bin | 10101001001101100001… |
… | …010000101111101000000 |
3 | 12010221202212010211210220 |
4 | 111021230022011331000 |
5 | 142303243430444300 |
6 | 3031422423223040 |
7 | 210004264110003 |
oct | 25115412057500 |
9 | 5127685124726 |
10 | 1453513531200 |
11 | 51048254a335 |
12 | 1b584a8a7a80 |
13 | a70b1570133 |
14 | 504c981b53a |
15 | 27c211d5da0 |
hex | 1526c285f40 |
1453513531200 has 84 divisors (see below), whose sum is σ = 4768735659360. Its totient is φ = 387603607040.
The previous prime is 1453513531193. The next prime is 1453513531243. The reversal of 1453513531200 is 21353153541.
It is a super-2 number, since 2×14535135312002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 151402860 + ... + 151412459.
Almost surely, 21453513531200 is an apocalyptic number.
1453513531200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1453513531200 is an abundant number, since it is smaller than the sum of its proper divisors (3315222128160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1453513531200 is a wasteful number, since it uses less digits than its factorization.
1453513531200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 302815344 (or 302815329 counting only the distinct ones).
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 1453513531200 its reverse (21353153541), we get a palindrome (1474866684741).
The spelling of 1453513531200 in words is "one trillion, four hundred fifty-three billion, five hundred thirteen million, five hundred thirty-one thousand, two hundred".
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