Base | Representation |
---|---|
bin | 101101110110000010011000… |
… | …011011010110011100000010 |
3 | 222102220012122220111220112220 |
4 | 231312002120123112130002 |
5 | 202411413012011100200 |
6 | 1552453251003431510 |
7 | 60316650620625651 |
oct | 5566023033263402 |
9 | 872805586456486 |
10 | 201625502050050 |
11 | 592759935a5461 |
12 | 1a744458825596 |
13 | 8867284740660 |
14 | 37b0a25225198 |
15 | 1849b1e4664a0 |
hex | b760986d6702 |
201625502050050 has 96 divisors (see below), whose sum is σ = 566837039065920. Its totient is φ = 47018740550400.
The previous prime is 201625502050009. The next prime is 201625502050067. The reversal of 201625502050050 is 50050205526102.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 201625502049993 and 201625502050020.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2720954881 + ... + 2721028980.
It is an arithmetic number, because the mean of its divisors is an integer number (5904552490270).
Almost surely, 2201625502050050 is an apocalyptic number.
201625502050050 is an abundant number, since it is smaller than the sum of its proper divisors (365211537015870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201625502050050 is a wasteful number, since it uses less digits than its factorization.
201625502050050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5441983908 (or 5441983903 counting only the distinct ones).
The product of its (nonzero) digits is 30000, while the sum is 33.
Adding to 201625502050050 its reverse (50050205526102), we get a palindrome (251675707576152).
The spelling of 201625502050050 in words is "two hundred one trillion, six hundred twenty-five billion, five hundred two million, fifty thousand, fifty".
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