Base | Representation |
---|---|
bin | 1001000111001100011… |
… | …10110111001101000000 |
3 | 1002221011111110021110220 |
4 | 10203212032313031000 |
5 | 20112212134113440 |
6 | 355500350023040 |
7 | 31422626435145 |
oct | 4434616671500 |
9 | 1087144407426 |
10 | 313100301120 |
11 | 11086aa59442 |
12 | 508207a7a80 |
13 | 236a9c1b189 |
14 | 11222d3a3cc |
15 | 82278248d0 |
hex | 48e63b7340 |
313100301120 has 112 divisors (see below), whose sum is σ = 994508803968. Its totient is φ = 83458529280.
The previous prime is 313100301091. The next prime is 313100301127. The reversal of 313100301120 is 21103001313.
It is a super-2 number, since 2×3131003011202 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 313100301120.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (313100301127) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2272605 + ... + 2406435.
Almost surely, 2313100301120 is an apocalyptic number.
313100301120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 313100301120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (497254401984).
313100301120 is an abundant number, since it is smaller than the sum of its proper divisors (681408502848).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
313100301120 is a wasteful number, since it uses less digits than its factorization.
313100301120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 136288 (or 136278 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 313100301120 its reverse (21103001313), we get a palindrome (334203302433).
The spelling of 313100301120 in words is "three hundred thirteen billion, one hundred million, three hundred one thousand, one hundred twenty".
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