Base | Representation |
---|---|
bin | 1001101000100010011… |
… | …01111010000001100000 |
3 | 1011122101001102021100220 |
4 | 10310101031322001200 |
5 | 20410342320340000 |
6 | 412020535243040 |
7 | 32625343652652 |
oct | 4642115720140 |
9 | 1148331367326 |
10 | 331001340000 |
11 | 118416699951 |
12 | 54197819480 |
13 | 252a07aca86 |
14 | 120405666d2 |
15 | 89241811a0 |
hex | 4d1137a060 |
331001340000 has 120 divisors (see below), whose sum is σ = 1085750792280. Its totient is φ = 88267008000.
The previous prime is 331001339989. The next prime is 331001340001. The reversal of 331001340000 is 43100133.
It is a tau number, because it is divible by the number of its divisors (120).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (331001340001) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 2698345 + ... + 2818344.
It is an arithmetic number, because the mean of its divisors is an integer number (9047923269).
Almost surely, 2331001340000 is an apocalyptic number.
331001340000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
331001340000 is an abundant number, since it is smaller than the sum of its proper divisors (754749452280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
331001340000 is an equidigital number, since it uses as much as digits as its factorization.
331001340000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5516722 (or 5516699 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 15.
Adding to 331001340000 its reverse (43100133), we get a palindrome (331044440133).
The spelling of 331001340000 in words is "three hundred thirty-one billion, one million, three hundred forty thousand".
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