Base | Representation |
---|---|
bin | 100101101001010011000001… |
… | …1100100011111010010000000 |
3 | 1121102102211202201001200101010 |
4 | 1023102212003210133102000 |
5 | 321400223401024002240 |
6 | 3132131341502040520 |
7 | 126514306220050452 |
oct | 11322460344372200 |
9 | 1542384681050333 |
10 | 331131301000320 |
11 | 96565aa5926377 |
12 | 3117b56a879140 |
13 | 1129c7173ac7a2 |
14 | 5baabaa3d62d2 |
15 | 284374204e280 |
hex | 12d298391f480 |
331131301000320 has 128 divisors (see below), whose sum is σ = 1080027092485440. Its totient is φ = 86248152797184.
The previous prime is 331131301000303. The next prime is 331131301000327. The reversal of 331131301000320 is 23000103131133.
It is a tau number, because it is divible by the number of its divisors (128).
It is not an unprimeable number, because it can be changed into a prime (331131301000327) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2005315339 + ... + 2005480458.
Almost surely, 2331131301000320 is an apocalyptic number.
331131301000320 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
331131301000320 is an abundant number, since it is smaller than the sum of its proper divisors (748895791485120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
331131301000320 is a wasteful number, since it uses less digits than its factorization.
331131301000320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4010795862 (or 4010795850 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 331131301000320 its reverse (23000103131133), we get a palindrome (354131404131453).
The spelling of 331131301000320 in words is "three hundred thirty-one trillion, one hundred thirty-one billion, three hundred one million, three hundred twenty", and thus it is an aban number.
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