Base | Representation |
---|---|
bin | 10010111111101010110101… |
… | …110001001011011111000000 |
3 | 101221210100202121222221220020 |
4 | 102333222311301023133000 |
5 | 41422210223322203032 |
6 | 453401453222013440 |
7 | 23411402062140411 |
oct | 2277526561133700 |
9 | 357710677887806 |
10 | 83540163475392 |
11 | 24689203437888 |
12 | 9452787877280 |
13 | 377ca5a6cba30 |
14 | 168b518c73808 |
15 | 99d110cd9b2c |
hex | 4bfab5c4b7c0 |
83540163475392 has 112 divisors (see below), whose sum is σ = 238755058614912. Its totient is φ = 25627007831040.
The previous prime is 83540163475283. The next prime is 83540163475411. The reversal of 83540163475392 is 29357436104538.
It is a super-3 number, since 3×835401634753923 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49732158 + ... + 51384509.
It is an arithmetic number, because the mean of its divisors is an integer number (2131741594776).
It is a 2-persistent number, because it is pandigital, and so is 2⋅83540163475392 = 167080326950784, but 3⋅83540163475392 = 250620490426176 is not.
Almost surely, 283540163475392 is an apocalyptic number.
It is an amenable number.
83540163475392 is an abundant number, since it is smaller than the sum of its proper divisors (155214895139520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
83540163475392 is a wasteful number, since it uses less digits than its factorization.
83540163475392 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101117026 (or 101117016 counting only the distinct ones).
The product of its (nonzero) digits is 65318400, while the sum is 60.
The spelling of 83540163475392 in words is "eighty-three trillion, five hundred forty billion, one hundred sixty-three million, four hundred seventy-five thousand, three hundred ninety-two".
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