Base | Representation |
---|---|
bin | 11011000100101010000… |
… | …01011100100010000010 |
3 | 10021221001011002121110121 |
4 | 31202111001130202002 |
5 | 110220034024321010 |
6 | 1551200051250454 |
7 | 124130356026610 |
oct | 15422501344202 |
9 | 3257034077417 |
10 | 930213120130 |
11 | 329557068168 |
12 | 1303465a9a2a |
13 | 69946050298 |
14 | 33045c6a6b0 |
15 | 192e4c023da |
hex | d89505c882 |
930213120130 has 64 divisors (see below), whose sum is σ = 2048436864000. Its totient is φ = 297023295168.
The previous prime is 930213120049. The next prime is 930213120197. The reversal of 930213120130 is 31021312039.
It is a super-2 number, since 2×9302131201302 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 930213120095 and 930213120104.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5848720 + ... + 6005659.
It is an arithmetic number, because the mean of its divisors is an integer number (32006826000).
Almost surely, 2930213120130 is an apocalyptic number.
930213120130 is an abundant number, since it is smaller than the sum of its proper divisors (1118223743870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
930213120130 is a wasteful number, since it uses less digits than its factorization.
930213120130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11854471.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 930213120130 its reverse (31021312039), we get a palindrome (961234432169).
The spelling of 930213120130 in words is "nine hundred thirty billion, two hundred thirteen million, one hundred twenty thousand, one hundred thirty".
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