Base | Representation |
---|---|
bin | 1010010010100000101111… |
… | …0000000101011000100000 |
3 | 1111001112012020201021121200 |
4 | 2210220023300011120200 |
5 | 2440323303044341000 |
6 | 40021104002121200 |
7 | 2245230115650222 |
oct | 244501360053040 |
9 | 44045166637550 |
10 | 11313141012000 |
11 | 3671970194003 |
12 | 1328690050200 |
13 | 640a948c74b9 |
14 | 2b17b7a6c412 |
15 | 149432871500 |
hex | a4a0bc05620 |
11313141012000 has 144 divisors (see below), whose sum is σ = 40150337579352. Its totient is φ = 3016837593600.
The previous prime is 11313141011987. The next prime is 11313141012013. The reversal of 11313141012000 is 21014131311.
It is a happy number.
11313141012000 is a `hidden beast` number, since 1 + 1 + 3 + 131 + 410 + 120 + 0 + 0 = 666.
It is an interprime number because it is at equal distance from previous prime (11313141011987) and next prime (11313141012013).
It can be written as a sum of positive squares in 4 ways, for example, as 552090608784 + 10761050403216 = 743028^2 + 3280404^2 .
It is a tau number, because it is divible by the number of its divisors (144).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 157090959 + ... + 157162958.
Almost surely, 211313141012000 is an apocalyptic number.
11313141012000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11313141012000 is an abundant number, since it is smaller than the sum of its proper divisors (28837196567352).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313141012000 is a wasteful number, since it uses less digits than its factorization.
11313141012000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 314253948 (or 314253927 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 11313141012000 its reverse (21014131311), we get a palindrome (11334155143311).
The spelling of 11313141012000 in words is "eleven trillion, three hundred thirteen billion, one hundred forty-one million, twelve thousand".
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